10 mL of 0.1 M extNa2 extSO4 is mixed with 10 mL of 0.2 M NaCl solution. If final solution has density 1 gm/mL. Then molarity of extNa^+ is:

May 16, 2026Chemistry

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May 16, 2026

Answer

10 mL = 0.010 \text{ L}$

Here are the solutions for questions 146 to 156.

Question 146: 10 mL of 0.1 M $\text{Na}_{2}SO_{4}$ is mixed with 10 mL of 0.2 M NaCl solution. If final solution has density 1 gm/mL. Then molarity of $\text{Na}^{+}$ is:

Step 1: Calculate moles of $\text{Na}^{+}$ from $\text{Na}_{2}SO_{4}$ . Volume of $\text{Na}_{2}SO_{4} = 10 mL = 0.010 \text{ L}$ Moles of $\text{Na}{2}SO{

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10 mL of 0.1 M Na_2SO_4 is mixed with 10 mL of 0.2 M NaCl solution. If final solution has density 1 gm/mL.

Asked on May 16, 2026Chemistry

This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.

ScanSolve AI AnswerAnswered on May 16, 2026

Here are the solutions for questions 146 to 156. Question 146: 10 mL of 0.1 M Na_2SO_4 is mixed with 10 mL of 0.2 M NaCl solution. If final solution has density 1 gm/mL. Then molarity of Na^+ is: Step 1: Calculate moles of Na^+ from Na_2SO_4. Volume of Na_2SO_4 = 10 mL = 0.010 L Moles of $Na_2SO_