This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
You're on a roll — Step 1: Calculate the molar mass of sodium hydroxide (NaOH). Molar mass of NaOH = Atomic mass of Na + Atomic mass of O + Atomic mass of H Molar mass of NaOH = 23.0 + 16.0 + 1.0 = 40.0 g/mol Step 2: Calculate the concentration of NaOH in mol/L. The concentration is given as 8 g per litre. Concentration of NaOH (mol/L) = Mass of NaOH per litreMolar mass of NaOH Concentration of NaOH (mol/L) = 8 g/L40.0 g/mol = 0.2 mol/L Step 3: Calculate the moles of NaOH used. The volume of NaOH solution used is 25 cm^3, which is 0.025 L. Moles of NaOH = Concentration × Volume (in L) Moles of NaOH = 0.2 mol/L × 0.025 L Moles of NaOH = 0.005 mol Step 4: Determine the moles of the dibasic acid. A dibasic acid reacts with NaOH in a 1:2 molar ratio. Let the dibasic acid be H_2A. The neutralization reaction is: H_2A + 2NaOH → Na_2A + 2H_2O From the equation, 1 mole of dibasic acid reacts with 2 moles of NaOH. Moles of acid = Moles of NaOH × 1 mol acid2 mol NaOH Moles of acid = 0.005 mol × (1)/(2) Moles of acid = 0.0025 mol Step 5: Calculate the relative molecular mass of the acid. The mass of the acid is 0.245 g. Relative molecular mass = Mass of acidMoles of acid Relative molecular mass = 0.245 g0.0025 mol Relative molecular mass = 98 g/mol The relative molecular mass of the acid is 98. That's all for today. Send me the next one tomorrow 📸