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Name the following organic compounds: a) H3C−CH=CH−CH3, b) H2C=CH−CH2−CH2−CH3, c) H2C=CH−CH2−CBr−CH3

Chemistry

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3 parts
a

But-2-ene\text{But-2-ene}

b

Pent-1-ene\text{Pent-1-ene}

c

4-bromopent-1-ene\text{4-bromopent-1-ene}

Step-by-step solution

9 steps

Here are the names for the compounds:

1. Name the following compounds:

Part a· 3 steps

H3C−CH=CH−CH3\text{H}_3\text{C} - \text{CH} = \text{CH} - \text{CH}_3

  1. Identify the longest carbon chain containing the double bond.

    The chain has 4 carbons.

  2. Number the carbons to give the double bond the lowest possible number.

    The double bond is between the second and third carbons from either end.

  3. Name the compound based on the chain length and double bond position.

    The parent chain is butane, and with a double bond at position 2, it is but-2-ene.

    • Name: But-2-ene\boxed{\text{But-2-ene}}

Part b

Pent-1-ene\text{Pent-1-ene}

H2C=CH−CH2−CH2−CH3\text{H}_2\text{C} = \text{CH} - \text{CH}_2 - \text{CH}_2 - \text{CH}_3

  1. Identify the longest carbon chain containing the double bond.

    The chain has 5 carbons.

  2. Number the carbons to give the double bond the lowest possible number.

    Numbering from the left gives the double bond at position 1.

  3. Name the compound based on the chain length and double bond position.

    The parent chain is pentane, and with a double bond at position 1, it is pent-1-ene.

    • Name: Pent-1-ene\boxed{\text{Pent-1-ene}}

Part c

4-bromopent-1-ene\text{4-bromopent-1-ene}

H2C=CH−CH2−CBr−CH3\text{H}_2\text{C} = \text{CH} - \text{CH}_2 - \text{CBr} - \text{CH}_3

Assumption: The structure is interpreted as H2C=CH−CH2−CBr−CH3\text{H}_2\text{C} = \text{CH} - \text{CH}_2 - \text{CBr} - \text{CH}_3, where the second "=" sign in the original image is a single bond to maintain carbon valency.

  1. Identify the longest carbon chain containing the double bond.

    The chain has 5 carbons.

  2. Number the carbons to give the double bond the lowest possible number and the substituent the lowest possible number.

    Numbering from the left gives the double bond at position 1. The bromine substituent is then at position 4.

  3. Name the compound, including the substituent and its position.

    The parent chain is pent-1-ene, and with a bromine at position 4, it is 4-bromopent-1-ene.

    • Name: 4-bromopent-1-ene\boxed{\text{4-bromopent-1-ene}}
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