This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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Alright — let's do this. I will solve for LEVEL 2. LEVEL 2: Arini neutralized hydrobromic acid (HBr) with beryllium hydroxide (Be(OH)_2) producing beryllium bromide (BeBr_2) and water. a) Write a word equation to represent the neutralization reaction. Step 1: Identify reactants and products. Reactants: Hydrobromic acid, Beryllium hydroxide Products: Beryllium bromide, Water Word equation: Hydrobromic acid + Beryllium hydroxide → Beryllium bromide + Water b) Write a skeleton equation to represent the neutralization reaction. Step 1: Write the chemical formulas for each substance. Hydrobromic acid: HBr Beryllium hydroxide: Be(OH)_2 Beryllium bromide: BeBr_2 Water: H_2O Skeleton equation: HBr + Be(OH)_2 → BeBr_2 + H_2O c) Balance the skeleton equation. Step 1: Count the atoms of each element on both sides of the skeleton equation. Reactants: H: 1 (from HBr) + 2 (from Be(OH)_2) = 3 Br: 1 Be: 1 O: 2 Products: H: 2 Br: 2 Be: 1 O: 1 Step 2: Balance the bromine atoms. There are 2 Br on the product side, so place a coefficient of 2 in front of HBr. 2HBr + Be(OH)_2 → BeBr_2 + H_2O Step 3: Recount the atoms. Reactants: H: 2 (from 2HBr) + 2 (from Be(OH)_2) = 4 Br: 2 Be: 1 O: 2 Products: H: 2 Br: 2 Be: 1 O: 1 Step 4: Balance the hydrogen and oxygen atoms. There are 4 H and 2 O on the reactant side. To balance, place a coefficient of 2 in front of H_2O. 2HBr + Be(OH)_2 → BeBr_2 + 2H_2O Step 5: Final check of atom counts. Reactants: H: 2 + 2 = 4 Br: 2 Be: 1 O: 2 Products: H: 2 × 2 = 4 Br: 2 Be: 1 O: 2 All atoms are balanced. Balanced equation: 2HBr + Be(OH)_2 → BeBr_2 + 2H_2O