Write the balanced molecular equation.

Mathematics

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Step-by-step solution

5 steps

  1. Write the balanced molecular equation.

    The given equation is already balanced.

    H2SO4(aq)+Fe(s)→FeSO4(aq)+H2(g)\text{H}_2\text{SO}_4(\text{aq}) + \text{Fe}(\text{s}) \rightarrow \text{FeSO}_4(\text{aq}) + \text{H}_2(\text{g})

  2. Dissociate all strong electrolytes into their ions.

    Strong acids and soluble ionic compounds dissociate in aqueous solution. Solids, liquids, and gases remain in their molecular form.
    H2SO4(aq)\text{H}_2\text{SO}_4(\text{aq}) dissociates into 2H+(aq)2\text{H}^+(\text{aq}) and SO42−(aq)\text{SO}_4^{2-}(\text{aq}).
    FeSO4(aq)\text{FeSO}_4(\text{aq}) dissociates into Fe2+(aq)\text{Fe}^{2+}(\text{aq}) and SO42−(aq)\text{SO}_4^{2-}(\text{aq}).
    Fe(s)\text{Fe}(\text{s}) and H2(g)\text{H}_2(\text{g}) do not dissociate.

  3. Write the complete ionic equation.

    2H+(aq)+SO42−(aq)+Fe(s)→Fe2+(aq)+SO42−(aq)+H2(g)2\text{H}^+(\text{aq}) + \text{SO}_4^{2-}(\text{aq}) + \text{Fe}(\text{s}) \rightarrow \text{Fe}^{2+}(\text{aq}) + \text{SO}_4^{2-}(\text{aq}) + \text{H}_2(\text{g})

  4. Identify and cancel out spectator ions.

    Spectator ions are ions that appear on both sides of the equation unchanged. In this reaction, SO42−(aq)\text{SO}_4^{2-}(\text{aq}) is a spectator ion.

  5. Write the net ionic equation.

    Remove the spectator ions to get the net ionic equation.

    2H+(aq)+Fe(s)→Fe2+(aq)+H2(g)\boxed{2\text{H}^+(\text{aq}) + \text{Fe}(\text{s}) \rightarrow \text{Fe}^{2+}(\text{aq}) + \text{H}_2(\text{g})}
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