To determine which chemical equation is balanced, we need to count the number of atoms for each element on both the reactant and product sides of each equation. A balanced equation has an equal number of atoms of each element on both sides.
Let's analyze each option:
-
A) 2Ca(OH)2+3H2SO4→CaSO4+4H2O
- Reactants:
- Ca: 2×1=2
- O: (2×2)+(3×4)=4+12=16
- H: (2×2)+(3×2)=4+6=10
- S: 3×1=3
- Products:
- Ca: 1×1=1
- O: (1×4)+(4×1)=4+4=8
- H: 4×2=8
- S: 1×1=1
- This equation is not balanced (e.g., Ca: 2 vs 1).
-
B) Ca(OH)2+2H2SO4→Ca(HSO4)2+4H2O
- Reactants:
- Ca: 1×1=1
- O: (1×2)+(2×4)=2+8=10
- H: (1×2)+(2×2)=2+4=6
- S: 2×1=2
- Products:
- Ca: 1×1=1
- O: (2×4)+(4×1)=8+4=12
- H: (2×1)+(4×2)=2+8=10
- S: 2×1=2
- This equation is not balanced (e.g., O: 10 vs 12).
-
C) 2Ca(OH)2+H2SO4→2CaSO4+2H2O
- Reactants:
- Ca: 2×1=2
- O: (2×2)+(1×4)=4+4=8
- H: (2×2)+(1×2)=4+2=6
- S: 1×1=1
- Products:
- Ca: 2×1=2
- O: (2×4)+(2×1)=8+2=10
- H: 2×2=4
- S: 2×1=2
- This equation is not balanced (e.g., O: 8 vs 10).
-
D) Ca(OH)2+H2SO4→CaSO4+2H2O
- Reactants:
- Ca: 1×1=1
- O: (1×2)+(1×4)=2+4=6
- H: (1×2)+(1×2)=2+2=4
- S: 1×1=1
- Products:
- Ca: 1×1=1
- O: (1×4)+(2×1)=4+2=6
- H: 2×2=4
- S: 1×1=1
- This equation is balanced. All atoms are equal on both sides.
The correct option is D.
Last free one today — make it count tomorrow, or type /upgrade for unlimited.