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An element X has two naturally occurring isotopes of 75% and 25% and 37x with a relative abundance of 75%. Find the exact relative atomic mass (RAM) of element X.

Chemistry

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4 parts
a

NaCl\text{NaCl}

b

Ca(NO3)2\text{Ca(NO}_3)_2

c

Al2O3\text{Al}_2\text{O}_3

d

CuSO4\text{CuSO}_4

35.50\text{35.50}

Step-by-step solution

3 steps

Haya Edith, twende na maswali haya ya kemia.

1. Kamilisha jedwali hapa chini kwa kuandika jina sahihi la elementi au radikali na valensi yake.

Elementi / RadikaliValensi
Magnesium (Mg)2
Klorini (Cl)1
Carbonate (CO3_3)2
Amonia (NH4_4)1
Alumini (Al)3

Kumbuka: Valensi ya Alumini ni 3, si 2 kama ilivyoandikwa kwenye picha.

2. Andika fomula za kemikali zifuatazo:

Part a

Sodium Chloride

Sodium (Na) ina valensi 1. Klorini (Cl) ina valensi 1.
Fomula: NaCl\boxed{\text{NaCl}}

Part b

Ca(NO3)2\text{Ca(NO}_3)_2

Calcium Nitrate

Kalsiamu (Ca) ina valensi 2. Nitrati (NO3_3) ina valensi 1.
Fomula: Ca(NO3)2\boxed{\text{Ca(NO}_3)_2}

Part c

Al2O3\text{Al}_2\text{O}_3

Aluminium Oxide

Alumini (Al) ina valensi 3. Oksijeni (O) ina valensi 2.
Fomula: Al2O3\boxed{\text{Al}_2\text{O}_3}

Part d

CuSO4\text{CuSO}_4

Copper(II) Sulfate

Shaba(II) (Cu) ina valensi 2. Sulfati (SO4_4) ina valensi 2.
Fomula: CuSO4\boxed{\text{CuSO}_4}

3. Taja michakato mitatu muhimu ya habari za kemikali ambazo mlinganyo wa kemikali ulioandikwa na kusawazishwa hutoa.

Mlinganyo wa kemikali uliosawazishwa hutoa habari zifuatazo:

  • Vitambulisho vya vitendanishi na bidhaa: Huonyesha ni vitu gani vinavyoitikia na ni vitu gani vipya vinavyoundwa.
  • Uwiano wa stoichiometric: Huonyesha uwiano wa moli (na hivyo uwiano wa masi) ambao vitendanishi huungana na bidhaa huundwa.
  • Uhifadhi wa masi: Huonyesha kwamba atomi hazipotei wala kuundwa upya, maana yake jumla ya masi ya vitendanishi ni sawa na jumla ya masi ya bidhaa.

9. Elementi X ina isotopu mbili zinazopatikana kiasili. 35X^{35}X ina wingi wa asilimia 75% na 37X^{37}X ina wingi wa asilimia [asilimia inayokosekana]. Tafuta masi halisi ya atomiki (RAM) ya elementi X.

  1. Pata wingi wa asilimia wa isotopu ya pili.

    Kwa kuwa kuna isotopu mbili tu, jumla ya asilimia lazima iwe 100%.
    Wingi wa 37X^{37}X = 100%−75%=25%100\% - 75\% = 25\%

  2. Tumia fomula ya kukokotoa Masi ya Atomiki Husika (RAM).

    RAM=(masi ya isotopu 1×wingi wa asilimia 1)+(masi ya isotopu 2×wingi wa asilimia 2)\text{RAM} = (\text{masi ya isotopu 1} \times \text{wingi wa asilimia 1}) + (\text{masi ya isotopu 2} \times \text{wingi wa asilimia 2}) RAM=(35×0.75)+(37×0.25)\text{RAM} = (35 \times 0.75) + (37 \times 0.25)
  3. Fanya hesabu.

    RAM=26.25+9.25\text{RAM} = 26.25 + 9.25 RAM=35.50\text{RAM} = 35.50

    Masi halisi ya atomiki (RAM) ya elementi X ni 35.50\boxed{\text{35.50}}.

    10. Eleza dhamana ya ioni.

    Dhamana ya ioni ni aina ya dhamana ya kemikali inayoundwa kati ya ioni mbili zenye chaji tofauti. Kawaida hutokea kati ya metali na isiyo-metali, ambapo elektroni huhamishwa kabisa kutoka atomi ya metali kwenda atomi ya isiyo-metali, na kusababisha kuundwa kwa kationi na anioni ambazo kisha huvutana kwa nguvu za kielektroniki.

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