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Calculate the number of moles for each element.

Chemistry

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Answer

CH1Cl3\text{CH}_1\text{Cl}_3

Step-by-step solution

3 steps

To find the empirical formula, we need to determine the simplest whole-number ratio of moles of each element in the compound.

  1. Calculate the number of moles for each element.

    We use the formula: moles=massrelative atomic mass\text{moles} = \frac{\text{mass}}{\text{relative atomic mass}}.
    For Carbon (C):

    Moles of C=2.4 g12 g/mol=0.2 mol\text{Moles of C} = \frac{2.4 \text{ g}}{12 \text{ g/mol}} = 0.2 \text{ mol}

    For Hydrogen (H):

    Moles of H=0.2 g1 g/mol=0.2 mol\text{Moles of H} = \frac{0.2 \text{ g}}{1 \text{ g/mol}} = 0.2 \text{ mol}

    For Chlorine (Cl):

    Moles of Cl=21.3 g35.5 g/mol=0.6 mol\text{Moles of Cl} = \frac{21.3 \text{ g}}{35.5 \text{ g/mol}} = 0.6 \text{ mol}
  2. Determine the simplest mole ratio by dividing by the smallest number of moles.

    The smallest number of moles is 0.2 mol (for C and H).
    For C:

    0.2 mol0.2 mol=1\frac{0.2 \text{ mol}}{0.2 \text{ mol}} = 1

    For H:

    0.2 mol0.2 mol=1\frac{0.2 \text{ mol}}{0.2 \text{ mol}} = 1

    For Cl:

    0.6 mol0.2 mol=3\frac{0.6 \text{ mol}}{0.2 \text{ mol}} = 3
  3. Write the empirical formula using these ratios.

    The ratio of C:H:Cl is 1:1:3.

    The empirical formula of the compound is CH1Cl3\text{CH}_1\text{Cl}_3.

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