Paper chromatography is a method of separating colours or dyes. What two properties should the components of…

Question

Paper chromatography is a method of separating colours or dyes. What two properties should the components of a mixture have that would make the separation possible?

ScanSolve AI Tutor · Accepted Answer

Ili kutofautisha kati ya dutu I (HOCH2CH3) na dutu II (HOOCCH2CH3) kwa kutumia sodium carbonate:

Tambua aina za misombo.
Dutu I, HOCH2CH3, ni ethanol, ambayo ni pombe. Dutu II, HOOCCH2CH3, ni asidi ya propanoiki, ambayo ni asidi ya kaboksili.
Ongeza sodium carbonate kwa kila dutu.
Asidi ya kaboksili humenyuka na kabonati kutoa gesi ya kaboni dioksidi. Pombe hazimenyuki na kabonati.
Angalia matokeo.
- Unapoongeza sodium carbonate kwenye dutu I (ethanol), hakutakuwa na mmenyuko unaoonekana.
- Unapoongeza sodium carbonate kwenye dutu II (asidi ya propanoiki), utaona kutoa povu (effervescence) kutokana na uzalishaji wa gesi ya kaboni dioksidi.
Mlinganyo wa mmenyuko kwa dutu II ni:
$\text{2HOOCCH}_2\text{CH}_3\text{(aq)} + \text{Na}_2\text{CO}_3\text{(s)} \longrightarrow \text{2NaOOCCH}_2\text{CH}_3\text{(aq)} + \text{H}_2\text{O(l)} + \text{CO}_2\text{(g)}$
Kwa hivyo, uwepo wa kutoa povu huonyesha asidi ya propanoiki, wakati kutokuwepo kwa mmenyuko huonyesha ethanol.

Paper chromatography is a method of separating colours or dyes. What two properties should the components of a mixture have that would make the separation possible?

Step-by-step solution

Tambua aina za misombo.

Ongeza sodium carbonate kwa kila dutu.

Angalia matokeo.

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