Provide calculation steps and general answers for titration and experimental data analysis, assuming reasonable values for missing data.

I will provide the steps and general answers for the questions. Since the tables are blank, I will outline the calculation methods and make reasonable assumptions for observations in Question 2 to demonstrate the process. You will need to substitute your actual experimental data into the formulas for numerical answers. --- QUESTION ONE Calculations Assumption for Table 1 (Mass of solid A): Mass of weighing bottle + solid A = 15.25 g Mass of weighing bottle alone = 9.10 g Mass of solid A = 15.25 g - 9.10 g = 6.15 g (This value is within the specified range of 6.0 to 6.25 g) Assumption for Table 3 (Titration readings): Approximate titre = 25.00 cm^3 First accurate titre = 24.60 cm^3 Second accurate titre = 24.50 cm^3 Mean titre = (24.60 + 24.50)/(2) = 24.55 cm^3 1) Using the titre, calculate the molarity of solution A and then solution B. Step 1: Calculate the molar mass of Na_2S_2O_3 · 5H_2O (solid A). M_r(Na_2S_2O_3 · 5H_2O) = (2 × 22.99) + (2 × 32.07) + (3 × 16.00) + (5 × (2 × 1.008 + 16.00)) M_r(Na_2S_2O_3 · 5H_2O) = 45.98 + 64.14 + 48.00 + (5 × 18.016) M_r(Na_2S_2O_3 · 5H_2O) = 45.98 + 64.14 + 48.00 + 90.08 = 248.20 g/mol Step 2: Calculate the moles of Na_2S_2O_3 · 5H_2O in 250 cm^3 of solution A. Moles of A = Mass of AM_r(Na_2S_2O_3 · 5H_2O) Moles of A = 6.15 g248.20 g/mol = 0.02478 mol Step 3: Calculate the molarity of solution A. Molarity of A = Moles of AVolume of solution A (in L) Molarity of A = 0.02478 mol0.250 L = 0.09912 mol/L Step 4: Calculate the moles of S_2O_3^2- used in the titration. Moles of S_2O_3^2- = Molarity of A × Mean titre (in L) Moles of S_2O_3^2- = 0.09912 mol/L × (24.55)/(1000) L = 0.002433 mol Step 5: Calculate the moles of I_2 reacted. From the equation: 2S_2O_3^2- + I_2 S_4O_6^2- + 2I^- The mole ratio S_2O_3^2- : I_2 is 2:1. Moles of I_2 = Moles of S_2O_3^2-2 Moles of I_2 = 0.002433 mol2 = 0.0012165 mol *Step