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Provide the IUPAC names for the following compounds: 1) CH3C(CH3)2CH2OH 2) Cyclohexane with two OH groups.
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10 stepsHere are the IUPAC names for the given compounds:
1)
Identify the longest carbon chain containing the hydroxyl () group.
The structure can be expanded as:
CH3 | CH3 - C - CH2 - OH | CH3The longest continuous chain containing the group has 3 carbons. This is a propane derivative.
Number the carbon chain starting from the end closest to the group.
The group is on the first carbon.
The chain is: .Identify and name the substituents.
There are two methyl () groups attached to carbon 2.
Combine the information to form the IUPAC name.
The parent alcohol is propan-1-ol. With two methyl groups at position 2, the name is 2,2-dimethylpropan-1-ol.
The IUPAC name is .
2) Cyclohexane with two groups
Identify the parent ring and functional groups.
The compound is a 6-membered carbon ring, which is a cyclohexane. It has two hydroxyl () groups, making it a diol.
Number the ring to give the hydroxyl groups the lowest possible locants.
The two groups are on adjacent carbons. Therefore, they are at positions 1 and 2.
Combine the information to form the IUPAC name.
The name is cyclohexane-1,2-diol.
The IUPAC name is .
3) Cyclopentane with four methyl groups
Identify the parent ring and substituents.
The compound is a 5-membered carbon ring, which is a cyclopentane. It has four methyl () groups attached to the ring.
Number the ring to give the substituents the lowest possible locants.
Starting from the top carbon as 1 and moving clockwise, the methyl groups are at positions 1, 2, 3, and 4.
(C1: top, C2: top-right, C3: bottom-right, C4: bottom-left, C5: top-left).Combine the information to form the IUPAC name.
There are four methyl groups, so "tetramethyl". Their positions are 1,2,3,4. The parent ring is cyclopentane.
The name is 1,2,3,4-tetramethylcyclopentane.The IUPAC name is .
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