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Provide the IUPAC names of these organic compounds
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14 stepsHere are the IUPAC names for the given organic compounds:
- Compound 1:
The structure is
CH₃-CH=CH-CH₂-CH₂-CH(CH₃)-CH₃.
Identify the longest carbon chain containing the double bond.
This chain has 7 carbons (heptene).
Number the chain to give the double bond the lowest possible number.
Numbering from the left, the double bond is between C2 and C3.
Identify and number the substituents.
There is a methyl group at C6.
Combine the name of the substituent with the parent chain and double bond position.
The name is 6-methylhept-2-ene. $$ \boxed{\text{6-methylhept-2-ene}} $$- Compound 2:
The structure is
CH₃CH₂CH=CHCH₂CH₂CH₃.
- Compound 2:
The structure is
Identify the longest carbon chain containing the double bond.
This chain has 7 carbons (heptene).
Number the chain to give the double bond the lowest possible number.
Numbering from the left, the double bond is between C3 and C4.
There are no substituents.
Combine the parent chain and double bond position.
The name is hept-3-ene. $$ \boxed{\text{hept-3-ene}} $$- Compound 3:
The structure is
CH₃-CH₂-CH₂-C(Br)(CH₃)-CH₃.
- Compound 3:
The structure is
Identify the longest carbon chain.
This chain has 5 carbons (pentane).
Number the chain to give the substituents the lowest possible numbers.
Numbering from the right, the substituents are at C2.
Identify and name the substituents.
There is a bromo group and a methyl group, both at C2.
Arrange substituents alphabetically and combine with the parent chain name.
The name is 2-bromo-2-methylpentane. $$ \boxed{\text{2-bromo-2-methylpentane}} $$- Compound 4: The structure is a six-membered ring with two double bonds.
Identify the parent ring.
It is a 6-membered ring with two double bonds, so it's a cyclohexadiene.
Number the ring to give the double bonds the lowest possible numbers.
Starting from one carbon of a double bond and proceeding through it, the double bonds are at positions 1 and 4.
The name is 1,4-cyclohexadiene.
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