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Chemistry

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Answer

-410\text{-410}

+121\text{+121}

+108\text{+108}

The question asks to identify the enthalpy change (ΔH\Delta H) values corresponding to three specific energy changes involved in the formation of sodium chloride (NaCl\text{NaCl}). These values are typically part of a Born-Haber cycle, which is used to calculate lattice energy.

  • Heat of formation: This is the enthalpy change when one mole of a compound is formed from its constituent elements in their standard states. For NaCl\text{NaCl}, this is the formation from solid sodium (Na(s)\text{Na}_{(\text{s})}) and chlorine gas (Cl2(g)\text{Cl}_{2(\text{g})}). The value -410\boxed{\text{-410}} represents the overall energy released when NaCl\text{NaCl} is formed.

  • Atomization energy: This is the enthalpy change required to produce one mole of gaseous atoms from an element in its standard state. For chlorine, it's the energy needed to break the Cl-Cl\text{Cl-Cl} bond in Cl2(g)\text{Cl}_{2(\text{g})} to form individual gaseous chlorine atoms (Cl(g)\text{Cl}_{(\text{g})}). The value +121\boxed{\text{+121}} is positive because energy is absorbed to break bonds.

  • Sublimation energy: This is the enthalpy change required to convert one mole of a solid directly into a gas. For sodium, it's the energy needed to change solid sodium (Na(s)\text{Na}_{(\text{s})}) into gaseous sodium atoms (Na(g)\text{Na}_{(\text{g})}). The value +108\boxed{\text{+108}} is positive because energy is absorbed to overcome intermolecular forces and change state.

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