Study the flow chart below and use it to answer the questions that follow.

Here are the solutions to the questions from the flow chart:

6. (b) Study the flow chart below and use it to answer the questions that follow.

• (i) Identify the organic compound K. Sodium propanoate ($\text{CH}_3\text{CH}_2\text{COONa}$) undergoes decarboxylation with sodalime ($\text{NaOH}/\text{CaO}$). This removes the carboxylate group, forming an alkane with one less carbon atom.

  • Organic compound K: Ethane ($\text{CH}_3\text{CH}_3$)

• (ii) Write the formula of M. Prop-1-ene ($\text{CH}_3\text{CH}=\text{CH}_2$) reacts with chlorine gas ($\text{Cl}_2(g)$) in an addition reaction across the double bond.

  • Formula of M: $\text{CH}_3\text{CHClCH}_2\text{Cl}$ (1,2-Dichloropropane)

• (iii) Give one reagent that can be used in

  • (a) Step I: Propanoic acid ($\text{CH}_3\text{CH}_2\text{COOH}$) is reduced to Propan-1-ol ($\text{CH}_3\text{CH}_2\text{CH}_2\text{OH}$).
    • Reagent: Lithium aluminium hydride ($\text{LiAlH}_4$)
  • (b) Step II: Propan-1-ol ($\text{CH}_3\text{CH}_2\text{CH}_2\text{OH}$) is oxidized to Propanoic acid ($\text{CH}_3\text{CH}_2\text{COOH}$).
    • Reagent: Acidified potassium dichromate(VI) ($\text{K}_2\text{Cr}_2\text{O}_7/\text{H}^+$) or acidified potassium permanganate(VII) ($\text{KMnO}_4/\text{H}^+$)

• (iv) Write the equation of the reaction in step III. Propan-1-ol ($\text{CH}_3\text{CH}_2\text{CH}_2\text{OH}$) reacts with sodium metal ($\text{Na}$).

  $$2\text{CH}_3\text{CH}_2\text{CH}_2\text{OH}(l) + 2\text{Na}(s) \rightarrow 2\text{CH}_3\text{CH}_2\text{CH}_2\text{ONa}(aq) + \text{H}_2(g)$$

6. (c) The structure below represents a type of a cleaning agent.
The structure is not visible in the provided image.