This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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Here are the solutions to the questions from the flow chart: 6. (b) Study the flow chart below and use it to answer the questions that follow. (i) Identify the organic compound K. Sodium propanoate (CH_3CH_2COONa) undergoes decarboxylation with sodalime (NaOH/CaO). This removes the carboxylate group, forming an alkane with one less carbon atom. Organic compound K: Ethane* (CH_3CH_3) (ii) Write the formula of M. Prop-1-ene (CH_3CH=CH_2) reacts with chlorine gas (Cl_2(g)) in an addition reaction across the double bond. Formula of M: CH_3CHClCH_2Cl (1,2-Dichloropropane) (iii) Give one reagent that can be used in (a) Step I: Propanoic acid (CH_3CH_2COOH) is reduced to Propan-1-ol (CH_3CH_2CH_2OH). Reagent: Lithium aluminium hydride* (LiAlH_4) (b) Step II: Propan-1-ol (CH_3CH_2CH_2OH) is oxidized to Propanoic acid (CH_3CH_2COOH). Reagent: Acidified potassium dichromate(VI) (K_2Cr_2O_7/H^+) or acidified potassium permanganate(VII)* (KMnO_4/H^+) (iv) Write the equation of the reaction in step III. Propan-1-ol (CH_3CH_2CH_2OH) reacts with sodium metal (Na). 2CH_3CH_2CH_2OH(l) + 2Na(s) → 2CH_3CH_2CH_2ONa(aq) + H_2(g) 6. (c) The structure below represents a type of a cleaning agent. The structure is not visible in the provided image. Last free one today — make it count tomorrow, or type /upgrade for unlimited.