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Sulfuric acid (H2SO4) is a strong acid and dissociates completely in water:

Chemistry

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Answer

7.5275×1022 ions\text{7.5275} \times 10^{22} \text{ ions}

Step-by-step solution

2 steps

...SO4_4

  1. Determine the moles of hydrogen ions (H+^+) produced.

    Sulfuric acid (H2_2SO4_4) is a strong acid and dissociates completely in water:

    H2SO4(aq)⟶2H+(aq)+SO42−(aq)\text{H}_2\text{SO}_4 \text{(aq)} \longrightarrow 2\text{H}^+ \text{(aq)} + \text{SO}_4^{2-} \text{(aq)}

    Each mole of H2_2SO4_4 produces 2 moles of H+^+ ions.

    Moles of H+ ions=2×0.0625 mol=0.125 mol\text{Moles of H}^+ \text{ ions} = 2 \times 0.0625 \text{ mol} = 0.125 \text{ mol}
  2. Calculate the number of hydrogen ions.

    Use Avogadro's number, which is approximately 6.022×10236.022 \times 10^{23} ions/mol.

    Number of H+ ions=Moles of H+ ions×Avogadro’s number\text{Number of H}^+ \text{ ions} = \text{Moles of H}^+ \text{ ions} \times \text{Avogadro's number} Number of H+ ions=0.125 mol×(6.022×1023 ions/mol)\text{Number of H}^+ \text{ ions} = 0.125 \text{ mol} \times (6.022 \times 10^{23} \text{ ions/mol}) Number of H+ ions=0.75275×1023 ions\text{Number of H}^+ \text{ ions} = 0.75275 \times 10^{23} \text{ ions} Number of H+ ions=7.5275×1022 ions\text{Number of H}^+ \text{ ions} = \boxed{\text{7.5275} \times 10^{22} \text{ ions}}
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