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Calculate the temperature at which water has a vapour pressure of 19 mm Hg.

Chemistry

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: Vapour pressure and temperature

Step 1: Identify the given values and the formula to use.
We are given:

  • Normal boiling point of water T1=373T_1 = 373 K (at P1=1P_1 = 1 atm =760= 760 mm Hg)
  • Enthalpy of vaporisation ΔHvap=40.67\Delta H_{vap} = 40.67 kJ/mol =40670= 40670 J/mol
  • Target vapour pressure P2=19P_2 = 19 mm Hg
  • Gas constant R=8.3R = 8.3 J K−1^{-1} mol−1^{-1}
  • We need to
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