This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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Step 1: Calculate the molar mass of sodium hydroxide (NaOH). The atomic masses are: Na = 22.99 \, g/mol, O = 16.00 \, g/mol, H = 1.01 \, g/mol. Molar mass of NaOH = 22.99 + 16.00 + 1.01 = 40.00 \, g/mol Step 2: Calculate the concentration of solution B (NaOH) in mol/dm^3. The mass concentration of NaOH is given as 2.00 \, g/dm^3. Concentration of B = Mass concentrationMolar mass Concentration of B = 2.00 \, g/dm^340.00 \, g/mol Concentration of B = 0.0500 \, mol/dm^3 The concentration of B is 0.0500 mol/dm^3. Step 3: Address parts (ii) and (iii). To calculate the pH of solution A and the amount of SO_4^2- ions that react, the concentration of solution A (H_2SO_4) is required. The concentration of A is determined from the titration data (specifically, the average volume of solution A used from the burette). Since no burette readings or average volume of A are provided in the problem description, parts (ii) and (iii) cannot be calculated. If the average volume of A (V_a) and the pipetted volume of B (V_b) were known, the calculations would proceed as follows: For (ii) pH of solution A: 1. Write the balanced chemical equation: H_2SO_4 (aq) + 2NaOH (aq) Na_2SO_4 (aq) + 2H_2O (l). 2. Use the titration formula: (C_a V_a)/(n_a) = (C_b V_b)/(n_b), where n_a = 1 and n_b = 2. 3. Calculate the concentration of A (C_a) using the known C_b (from part i), V_b (pipette volume, e.g., 25.00 \, cm^3), and the experimental V_a. 4. Since H_2SO_4 is a diprotic acid, [H^+] = 2 × C_a. 5. Calculate pH = -_10[H^+]. For (iii) amount of SO_4^2- ions that react: 1. In an acid-base neutralization reaction, SO_4^2- ions are spectator ions and do not chemically react (i.e., their chemical form does not change). 2. If the question implies the amount of SO_4^2- ions present in the volume of acid that reacted, then: Moles of SO_4^2- = Moles of H_2SO_4 reacted. Moles of H_2SO_4 reacted = C_a × V_a (where V_a is the average volume of A used, in dm^3). This calculation also requires the concentration of A (C_a) and the average volume of A used (V_a), which are not provided. Send me the next one 📸