A 25.0 cm³ aliquot of NaOH solution was titrated against 0.100 mol/dm³ HCl. If the average titre of HCl used was 20.00 cm³, what is the concentration of the NaOH solution in mol/dm³?

May 18, 2026Chemistry

ScanSolve AI Answer

May 18, 2026

Answer

0.025 $\text{dm}^3$

Hey Blessing😍😍, good to see you again.

Let's break down this titration problem step by step. Since the burette readings are not provided, I will assume an average titre value for the acid.

Assumed Volume of B pipetted ( $\text{V}_B$ ): 25.0 $\text{cm}^3$ = 0.025 $\text{dm}^3$
Assumed Average Volume of A used ( $\text{V}_A$ ): 20.00 $\text{cm}^3$ = 0.020 $\text{dm}^3$

Molar Masses:

$\text{NaOH}$ : $23 (Na) + 16 (\

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Hey Blessing😍😍, good to see you again. Let's break down this titration problem step by step.

Asked on May 18, 2026Chemistry

This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.

ScanSolve AI AnswerAnswered on May 18, 2026

Hey Blessing😍😍, good to see you again. Let's break down this titration problem step by step. Since the burette readings are not provided, I will assume an average titre value for the acid. Assumed Volume of B pipetted (V_B): 25.0 cm^3 = 0.025 dm^3 Assumed Average Volume of A used (V_A): 20.00 cm^3 = 0.020 dm^3 Molar Masses: NaOH: $23 (Na) + 16 (\