This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Step 1: Complete the table by calculating the values for 1/t. The reaction rate is often taken as inversely proportional to the time taken for the reaction to complete. Rate = (1)/(Time(t)) Expt 1: 1/t = (1)/(70 s) ≈ 0.0143 s^-1 Expt 2: 1/t = (1)/(74 s) ≈ 0.0135 s^-1 Expt 3: 1/t = (1)/(78 s) ≈ 0.0128 s^-1 Expt 4: 1/t = (1)/(82 s) ≈ 0.0122 s^-1 Expt 5: 1/t = (1)/(86 s) ≈ 0.0116 s^-1 Expt 6: 1/t = (1)/(90 s) ≈ 0.0111 s^-1 The temperature column is left blank as the values are not provided and cannot be determined from the image. Here is the completed table: | Experiment | Volume of solution I / cm³ | Volume of water / cm³ | Volume of dilute H₂SO₄ / cm³ | Volume of starch / cm³ | Volume of solution J / cm³ | Time, t / sec | Temperature / °C | 1/t / s⁻¹ | | :--------- | :------------------------- | :-------------------- | :--------------------------- | :--------------------- | :------------------------- | :------------ | :--------------- | :-------- | | 1 | 30.0 | 10.0 | 20 | 5.0 | 10.0 | 70 | | 0.0143 | | 2 | 26.0 | 10.0 | 20 | 5.0 | 10.0 | 74 | | 0.0135 | | 3 | 22.0 | 10.0 | 20 | 5.0 | 10.0 | 78 | | 0.0128 | | 4 | 18.0 | 10.0 | 20 | 5.0 | 10.0 | 82 | | 0.0122 | | 5 | 14.0 | 10.0 | 20 | 5.0 | 10.0 | 86 | | 0.0116 | | 6 | 10.0 | 10.0 | 20 | 5.0 | 10.0 | 90 | | 0.0111 | Step 2: Plot a graph of 1/t (vertical axis) against the volume of solution I (horizontal axis). To plot the graph: Draw and label the horizontal axis (x-axis) as "Volume of solution I / cm³". Choose a suitable scale that covers the range from 10.0 to 30.0 cm³. Draw and label the vertical axis (y-axis) as "Reaction Rate, 1/t / s⁻¹". Choose a suitable scale that covers the range from approximately 0.011 to 0.015 s⁻¹. Plot the following points from the completed table: (30.0, 0.0143) (26.0, 0.0135) (22.0, 0.0128) (18.0, 0.0122) (14.0, 0.0116) (10.0, 0.0111) Draw a smooth curve or line of best fit through the plotted points. The graph should show that as the volume of solution I (and thus the concentration of iodate ions) decreases, the reaction rate (1/t) also decreases. What's next?