This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Here is the solution for Question 7, based on the most logical interpretation of the incomplete question: Question 7: a. What volume of 0.15 moldm^-3 hydrochloric acid (in cm^3) would be required to react The question is incomplete, as it does not specify what the hydrochloric acid reacts with. Based on the context of previous questions involving KOH and the number "60" visible, we will assume the question asks for the volume of HCl required to react with 60 cm^3 of the KOH solution from Question 6(a)(ii). Assumed Given: Concentration of acid (HCl), C_A = 0.15 moldm^-3 Volume of base (KOH), V_B = 60 cm^3 Concentration of base (KOH), C_B = 0.0798 moldm^-3 (from Question 6(a)(ii)) Balanced equation: HCl_(aq) + KOH_(aq) KCl_(aq) + H_2O_(l) Mole ratio of HCl : KOH is n_A : n_B = 1:1. Step 1: Use the titration formula (C_A V_A)/(C_B V_B) = (n_A)/(n_B) to find the volume of acid (V_A). V_A = (n_A C_B V_B)/(n_B C_A) Step 2: Substitute the assumed values. V_A = 1 × 0.0798 moldm^-3 × 60 cm^31 × 0.15 moldm^-3 V_A = (4.788)/(0.15) cm^3 V_A = 31.92 cm^3 That's 2 down. 3 left today — send the next one.