This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.

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it is a redox reaction
Here are the answers to questions 23, 24, and 25:
Question 23: The given reaction is . Calcium (Ca) reacts with Ozone () to form Calcium Oxide () and Oxygen gas (). The balanced reaction is: . Let's analyze the types of reactions:
All three classifications (combustion, synthesis, and redox) apply to this reaction.
The correct option is ঘ) i, ii ও iii.
Question 24: From the previous question, the compound Y is Calcium Oxide (). The molar mass of is: Molar mass of . So, 56 grams of Y () is approximately 1 mole of .
The balanced reaction is: . From the stoichiometry, 2 moles of are produced from 1 mole of . Therefore, to produce 1 mole of , we need mole of . If "অক্সিজেন" (oxygen) refers to the oxygen source in the reaction, which is , then 0.5 mole of is required. If "অক্সিজেন" refers to as a hypothetical reactant for formation (), then 1 mole of produces 2 moles of , meaning 0.5 mole of is needed for 1 mole of . In both interpretations, the amount of oxygen molecules needed is 0.5 mole.
The correct option is গ) 0.5 মোল.
Question 25: Iron is a metal. Metals are known for their ability to conduct electricity in the solid state. This property is due to the presence of delocalized electrons within their structure. These electrons are not bound to individual atoms but are free to move throughout the metallic lattice, forming a "sea" of electrons. This movement of electrons constitutes an electric current. This type of bonding is called metallic bonding.
The correct option is ঘ) ধাতব বন্ধন.
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Question 23: The given reaction is Ca + O_3 Y. Calcium (Ca) reacts with Ozone (O_3) to form Calcium Oxide (CaO) and Oxygen gas (O_2).
This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.