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The set-up below was used to investigate the properties of hydrogen. (i) State two observations that was made in the combustion tube as the reaction progressed

Chemistry

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13. Below is a simplified scheme of solvay process. Study it and answer the questions that follow.

  • 13a) Identify gas R. In the Solvay process, ammonia solution is reacted with carbon dioxide (Gas R) and brine to form ammonium bicarbonate, which then reacts further. Gas R: Carbon dioxide (CO2)\boxed{\text{Carbon dioxide (CO}_2\text{)}}

  • 13b) Write an equation for process III. Process III involves the thermal decomposition of sodium bicarbonate (NaHCO3NaHCO_3) to produce sodium carbonate (Na2CO3Na_2CO_3), water, and carbon dioxide.

    2NaHCO3(s)→heatNa2CO3(s)+H2O(g)+CO2(g)2\text{NaHCO}_3\text{(s)} \xrightarrow{\text{heat}} \text{Na}_2\text{CO}_3\text{(s)} + \text{H}_2\text{O(g)} + \text{CO}_2\text{(g)}
  • 13c) Give one use of sodium carbonate. Sodium carbonate is a versatile industrial chemical. One use: Manufacture of glass\boxed{\text{Manufacture of glass}} (Other uses include making detergents, softening hard water, and in paper manufacturing).

14. The set-up below was used to investigate the properties of hydrogen.

  • 14i) State two observations that were made in the combustion tube as the reaction progressed. In the combustion tube, hydrogen gas reacts with heated Lead(II) oxide (PbO). Hydrogen acts as a reducing agent, reducing the lead(II) oxide to lead metal and forming water. H2(g)+PbO(s)→heatPb(s)+H2O(g)\text{H}_2\text{(g)} + \text{PbO(s)} \xrightarrow{\text{heat}} \text{Pb(s)} + \text{H}_2\text{O(g)}
    1. The yellow/orange solid (Lead(II) oxide) turned into a grey solid (Lead metal).
    2. Colourless liquid droplets (water) were observed on the cooler parts of the combustion tube.
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