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What are the solutions to the following questions? 1(a) Classify organisms into kingdoms. 1(b) List three plant cell structures. 2(i) Name molecules NF3, SO3, SiF4. 2(ii) Name atom particles, their ma

Chemistry

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vi

43 or 1.33\frac{4}{3} \text{ or } 1.33

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Here are the solutions to the questions:

1 (a) Classify the following organisms into their respective kingdoms:

Part i

Yeast: *Fungi

Part ii

Penicillium: *Fungi

Part iii

Rhizobium: Monera (Bacteria)

Part iv

Mushroom: *Fungi

Part v

Amoeba: *Protista

Part vi

43 or 1.33\frac{4}{3} \text{ or } 1.33

Fish: *Animalia

1 (b) List three structures found in plant cell only [6 marks]

  • Cell wall
  • Chloroplasts
  • Large central vacuole

2 (i) Name each of the following molecules.

  • (α) NF3_3: Nitrogen trifluoride
  • (β) SO3_3: Sulfur trioxide
  • (γ) SiF4_4: Silicon tetrafluoride

2 (ii) Give the names of the fundamental particles of an atom and their relative masses and charges. [6 marks]

  • Proton: Relative mass ≈1\approx 1, Relative charge +1+1
  • Neutron: Relative mass ≈1\approx 1, Relative charge 0
  • Electron: Relative mass ≈11836\approx \frac{1}{1836}, Relative charge −1-1

3 Calculate the relative density of the liquid. [3 marks]

  1. Determine the density of the plank (ρp\rho_p) using its flotation in water.

    Let VV be the total volume of the plank, and ρw\rho_w be the density of water.
    When floating, the buoyant force equals the weight of the plank.

    Weight of plank=Weight of water displaced\text{Weight of plank} = \text{Weight of water displaced} ρpVg=ρw(23V)g\rho_p V g = \rho_w \left(\frac{2}{3}V\right) g ρp=23ρw\rho_p = \frac{2}{3} \rho_w
  2. Determine the density of the plank using its flotation in the unknown liquid.

    Let ρL\rho_L be the density of the unknown liquid.

    Weight of plank=Weight of liquid displaced\text{Weight of plank} = \text{Weight of liquid displaced} ρpVg=ρL(12V)g\rho_p V g = \rho_L \left(\frac{1}{2}V\right) g ρp=12ρL\rho_p = \frac{1}{2} \rho_L
  3. Equate the expressions for ρp\rho_p to find the relationship between ρL\rho_L and ρw\rho_w.

    23ρw=12ρL\frac{2}{3} \rho_w = \frac{1}{2} \rho_L ρL=23×2ρw\rho_L = \frac{2}{3} \times 2 \rho_w ρL=43ρw\rho_L = \frac{4}{3} \rho_w
  4. Calculate the relative density of the liquid.

    Relative density of liquid =Density of liquidDensity of water= \frac{\text{Density of liquid}}{\text{Density of water}}

    Relative density=ρLρw=43ρwρw=43 or 1.33\text{Relative density} = \frac{\rho_L}{\rho_w} = \frac{\frac{4}{3} \rho_w}{\rho_w} = \boxed{\frac{4}{3} \text{ or } 1.33}

    4 (i) Distinguish between a grain and a cereal.
    A grain is a small, hard, dry seed, with or without an attached hull or fruit layer, harvested for human or animal consumption. A cereal is a type of grain that comes from grasses cultivated for their edible components, such as wheat, rice, or maize. All cereals are grains, but not all grains are cereals (e.g., legumes like lentils are grains but not cereals).

    4 (ii) State one example of a grain.
    Maize (Corn)

    4 (iii) Mention four uses of the named grain in d (ii). [5 marks]
    (Assuming "d (ii)" refers to "4 (ii)", and the named grain is Maize)

    • Food for human consumption (e.g., cornmeal, sweet corn, popcorn).
    • Animal feed for livestock.
    • Production of ethanol (biofuel).
    • Source of corn oil and corn starch.

    5 (i) Define the following terms

    • (α) Mitosis: Mitosis is a type of cell division that results in two daughter cells each having the same number and kind of chromosomes as the parent nucleus. It is essential for growth, repair, and asexual reproduction.
    • (β) Meiosis: Meiosis is a type of cell division that reduces the number of chromosomes in the parent cell by half and produces four haploid gamete cells. This process is crucial for sexual reproduction.

    5 (ii) Mention two ways in which meiosis is significant. [6 marks]

    • Meiosis ensures genetic variation in offspring through processes like crossing over and independent assortment of chromosomes, leading to diverse traits within a species.
    • It maintains a constant chromosome number across generations in sexually reproducing organisms by halving the chromosome number in gametes, so that when two gametes fuse during fertilization, the diploid number is restored.

    6 (i) (α) Explain the term isomers.
    Isomers are compounds that have the same molecular formula but different structural formulas or different arrangements of atoms in space. This difference in arrangement leads to distinct chemical and physical properties.

    6 (i) (β) Write down structures for three isomers of hexane. [6 marks]
    Hexane has the molecular formula C6_6H14_{14}.

    1. n-Hexane (straight chain)

      CH3CH2CH2CH2CH2CH3\text{CH}_3\text{CH}_2\text{CH}_2\text{CH}_2\text{CH}_2\text{CH}_3
    2. 2-Methylpentane

      CH3∣CH3CH2CH2CHCH3\begin{matrix} & \text{CH}_3 \\ & | \\ \text{CH}_3\text{CH}_2\text{CH}_2\text{CH}\text{CH}_3 \end{matrix}
    3. 2,3-Dimethylbutane

      CH3CH3∣∣CH3CHCHCH3\begin{matrix} & \text{CH}_3 & \text{CH}_3 \\ & | & | \\ \text{CH}_3\text{CH}\text{CH}\text{CH}_3 \end{matrix}
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