This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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Here are the solutions to the problems. Question 6: The specific gravity of concentrated tetraoxosulphate (VI) acid is 1.84. Calculate the volume of tetraoxosulphate (VI) acid required to make 0.01M H_2SO_4, if the percentage purity of H_2SO_4 is 98.7. Assumption: The question is incomplete as it does not specify the final volume of the 0.01 M H_2SO_4 solution to be prepared. We will assume a target volume of 1 L (1000 mL) for the dilute solution. Step 1: Calculate the molar mass of H_2SO_4. Molar mass of H_2SO_4 = 2(1.01 g/mol for H) + 32.07 g/mol for S + 4(16.00 g/mol for O) = 2.02 + 32.07 + 64.00 = 98.09 g/mol Step 2: Calculate the molarity of the concentrated H_2SO_4 solution. Density of concentrated H_2SO_4 = Specific gravity × Density of water = 1.84 × 1 g/mL = 1.84 g/mL. Mass of 1 L (1000 mL) of concentrated acid = Density × Volume = 1.84 g/mL × 1000 mL = 1840 g Mass of pure H_2SO_4 in 1 L of concentrated acid = Mass of solution × Purity percentage = 1840 g × (98.7)/(100) = 1816.08 g Moles of pure H_2SO_4 in 1 L of concentrated acid = MassMolar mass = 1816.08 g98.09 g/mol = 18.515 mol Molarity of concentrated H_2SO_4 (M_1) = 18.515 M. Step 3: Calculate the volume of concentrated acid required using the dilution formula. We use the dilution formula: M_1V_1 = M_2V_2 Where: M_1 = 18.515 M (molarity of concentrated acid) V_1 = ? (volume of concentrated acid required) M_2 = 0.01 M (target molarity of dilute acid) V_2 = 1000 mL (target volume of dilute acid, assumed) 18.515 M × V_1 = 0.01 M × 1000 mL V_1 = 0.01 M × 1000 mL18.515 M V_1 = 10 mL18.515 V_1 = 0.53999 mL Rounding to three significant figures: V_1 = 0.540 mL The volume of concentrated tetraoxosulphate (VI) acid required is 0.540 mL. Question 7: A solution of ammonia in water with a density of 0.93 g/cm^3 contained 18% by mass of ammonia. What volume of this solution is required to form 30g of ammonium tetraoxosulphate(VI) based on the reaction: 2NH_3 + H_2SO_4 → (NH_4)_2SO_4. Step 1: Calculate the molar mass of ammonium tetraoxosulphate(VI), (NH_4)_2SO_4. Molar mass of (NH_4)_2SO_4 = $2(14.01 g/