What are the units of kc

Chemistry

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Answer

L/mol\text{L/mol}

Step-by-step solution

3 steps

  1. Write down the equilibrium expression and the units for concentration.

    The equilibrium expression is Kc=[SO3]2[SO2]2[O2]K_c = \frac{[\text{SO}_3]^2}{[\text{SO}_2]^2[\text{O}_2]}.
    The unit for concentration is mol/L\text{mol/L}.

  2. Substitute the units into the equilibrium expression.

    Kc units=(mol/L)2(mol/L)2⋅(mol/L)K_c \text{ units} = \frac{(\text{mol/L})^2}{(\text{mol/L})^2 \cdot (\text{mol/L})}

  3. Simplify the units.

    Kc units=(mol/L)2(mol/L)2+1K_c \text{ units} = \frac{(\text{mol/L})^2}{(\text{mol/L})^{2+1}} Kc units=(mol/L)2(mol/L)3K_c \text{ units} = \frac{(\text{mol/L})^2}{(\text{mol/L})^3} Kc units=(mol/L)2−3K_c \text{ units} = (\text{mol/L})^{2-3} Kc units=(mol/L)−1K_c \text{ units} = (\text{mol/L})^{-1} Kc units=L/molK_c \text{ units} = \text{L/mol}

    The units of KcK_c are L/mol\boxed{\text{L/mol}}.

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