This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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You're on a roll — here is the solution to the next question: Q.1 (viii) By which formula the molal elevation constant (Kb) can be calculated Step 1: Recall the formula for elevation in boiling point. The elevation in boiling point ( T_b) is given by: T_b = K_b × m where K_b is the molal elevation constant and m is the molality of the solution. Step 2: Express molality (m) in terms of mass and molar mass. Molality (m) is defined as moles of solute per kilogram of solvent. m = moles of solutemass of solvent (in kg) If W_s is the mass of the solute, M_r is the molar mass of the solute, and W_w is the mass of the solvent in grams, then: Moles of solute = (W_s)/(M_r) Mass of solvent (in kg) = (W_w)/(1000) So, m = (W_s / M_r)/(W_w / 1000) = (W_s × 1000)/(M_r × W_w) Step 3: Substitute the expression for molality into the boiling point elevation formula and rearrange for K_b. T_b = K_b × (W_s × 1000)/(M_r × W_w) Rearranging to solve for K_b: K_b = ( T_b × M_r × W_w)/(1000 × W_s) Comparing this with the given options, option (a) matches this formula. The final answer is (a) (M_r × T_b × W_w)/(1000 × W_s). That's all the questions from the image! Drop the next question.