Given the equation 2So +O reversible gives 2SO write down the equilibrium expression for Kc

The equilibrium expression for the reaction $2\text{SO}_{2}(\text{g}) + \text{O}_{2}(\text{g}) \rightleftharpoons 2\text{SO}_{3}(\text{g})$ is given by:

$$K_c = \frac{[\text{SO}_3]^2}{[\text{SO}_2]^2[\text{O}_2]}$$