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To calculate the amount in moles of ethanoic acid, we need two pieces of information that were not provided in the previous steps:

Chemistry

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Answer

0.002405 mol0.002405 \text{ mol}

Step-by-step solution

2 steps

To calculate the amount in moles of ethanoic acid, we need two pieces of information that were not provided in the previous steps:

  1. The concentration of the ethanoic acid solution (Solution A).
  2. Your average volume of A used from your titration results.

Since these values are not available, I will demonstrate the calculation using assumed values. You should substitute your actual experimental values into the formula.

  • Assumed Concentration of Ethanoic Acid (Solution A): 0.100 mol/dm30.100 \text{ mol/dm}^3
  • Assumed Average Volume of A used (from previous example): 24.05 cm324.05 \text{ cm}^3

  1. Convert the average volume of A used from cm3\text{cm}^3 to dm3\text{dm}^3.

    Volume of A in dm3=Average volume of A used (cm3)1000 cm3/dm3\text{Volume of A in dm}^3 = \frac{\text{Average volume of A used (cm}^3)}{1000 \text{ cm}^3/\text{dm}^3} Volume of A in dm3=24.05 cm31000 cm3/dm3=0.02405 dm3\text{Volume of A in dm}^3 = \frac{24.05 \text{ cm}^3}{1000 \text{ cm}^3/\text{dm}^3} = 0.02405 \text{ dm}^3

  2. Calculate the amount in moles of ethanoic acid.

    The formula for moles is:

    Moles=Concentration×Volume (in dm3)\text{Moles} = \text{Concentration} \times \text{Volume (in dm}^3)

    Using the assumed values:

    Moles of ethanoic acid=0.100 mol/dm3×0.02405 dm3\text{Moles of ethanoic acid} = 0.100 \text{ mol/dm}^3 \times 0.02405 \text{ dm}^3 Moles of ethanoic acid=0.002405 mol\text{Moles of ethanoic acid} = \boxed{0.002405 \text{ mol}}

    Remember to use your actual concentration of ethanoic acid and your calculated average volume of A used to get your specific answer.

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