To calculate the enthalpy of formation of methanol, CH_3OH(l), we will use Hess's Law by manipulating the given combustion reactions. The target reaction is:
This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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To calculate the enthalpy of formation of methanol, CH$_3$OH(l), we will use Hess's Law by manipulating the given combustion reactions. The target reaction is:
$$ \text{C(s)} + 2\text{H}_2\text{(g)} + \frac{1}{2}\text{O}_2\text{(g)} \rightarrow \text{CH}_3\text{OH(l)} $$
The given reactions are:
1. $$ \text{CH}_3\text{OH(l)} + \frac{3}{2}\text{O}_2\text{(g)} \rightarrow \text{CO}_2\text{(g)} + 2\text{H}_2\text{O(l
