To calculate the enthalpy of formation of methanol, CH₃OH(l), we will use Hess's Law by manipulating the given combustion reactions. The target reaction is:

To calculate the enthalpy of formation of methanol, CH$_3$OH(l), we will use Hess's Law by manipulating the given combustion reactions. The target reaction is:

$$\text{C(s)} + 2\text{H}_2\text{(g)} + \frac{1}{2}\text{O}_2\text{(g)} \rightarrow \text{CH}_3\text{OH(l)}$$

The given reactions are:

1. $$$$