We read your photo as:

Using Hess's Law, calculate the heat of formation of propane given the following reactions: 1. C(s) + O2(g) -> CO2(g), ΔH = -393.5 kJ/mol 2. H2(g) + 1/2 O2(g) -> H2O(l), ΔH = -285.8 kJ/mol 3. C3H8(g)

Chemistry

ScanSolve AI Answer

You've provided the additional data needed to solve part (b) of question 7. Let's calculate the heat of formation of propane using Hess's Law.

The target reaction for the heat of formation of propane (C3H8\text{C}_3\text{H}_8) is:

3C(s)+4H2(g)⟶C3H8(g)ΔHf∘(C3H8)3\text{C(s)} + 4\text{H}_2\text{(g)} \longrightarrow \text{C}_3\text{H}_8\text{(g)} \quad \Delta H_f^\circ (\text{C}_3\text{H}_8)

We have the following given reactions and their enthalpy changes:

  1. $\text{C(s)} + \text
Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp