With an example explain Michael reaction in a simplest way in term of synthesis
This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
The Michael reaction is a conjugate addition reaction where a nucleophile adds to an $\alpha, \beta$-unsaturated carbonyl compound.
Example:
Consider the reaction between diethyl malonate (a nucleophile) and methyl acrylate (an $\alpha, \beta$-unsaturated carbonyl compound) in the presence of a base like sodium ethoxide.
Step 1: The base deprotonates diethyl malonate to form a carbanion.
$$ \text{CH}_2(\text{COOEt})_2 + \text{NaOEt} \rightarrow [\text{CH}(\text{COOEt})_2]^- \text{Na}^+ + \text{EtOH} $$
Step 2: The carbanion attacks the $\beta$-carbon of methyl acrylate (conjugate addition).
$$ [\text{CH}(\text{COOEt})_2]^- + \text{CH}_2=\text{CHCOOMe} \rightarrow (\text{EtOOC})_2\text{CH}-\text{CH}_2-\text{CH}^--\text{COOMe} $$
Step 3: The resulting enolate is protonated.
$$ (\text{EtOOC})_2\text{CH}-\text{CH}_2-\text{CH}^--\text{COOMe} + \text{EtOH} \rightarrow (\text{EtOOC})_2\text{CH}-\text{CH}_2-\text{CH}_2-\text{COOMe} + \text{EtO}^- $$
This reaction forms a new carbon-carbon bond, extending the carbon chain.
