Relative atomic mass is the topic of of today I want you to explain it write a note a brief note on it and then calculation the calculation aspects explain the breaking down in a layman terms for like a child then give me an example because this is for a post utme exam something like that something related just explain and give me an example to write on this topic

Chemistry

ScanSolve AI Answer

Answer

35.45

Step-by-step solution

5 steps

Relative atomic mass (RAM) is the average mass of atoms of an element, taking into account the masses and natural abundances of its isotopes. It is a ratio, comparing the average mass of an atom of an element to 112\frac{1}{12} the mass of a carbon-12 atom.

To understand how it's calculated, imagine you have a basket of apples, but some are slightly heavier than others. If you want to find the average weight of an apple from the basket, you can't just pick one of each type and average their weights. You need to know how many of each type of apple you have. If there are many more heavy apples, the average weight will be closer to the weight of the heavy apples. In chemistry, atoms of the same element can have slightly different masses (these are called isotopes). To find the relative atomic mass, we multiply the mass of each isotope by how common it is (its percentage abundance), add these values together, and then divide by 100. This gives us a weighted average that reflects the natural mix of isotopes.

Here is an example calculation:

Example:
Chlorine has two main isotopes: Chlorine-35 and Chlorine-37.

  • Chlorine-35 has an isotopic mass of 34.9689 amu34.9689 \text{ amu} and a natural abundance of 75.77%75.77\%.
  • Chlorine-37 has an isotopic mass of 36.9659 amu36.9659 \text{ amu} and a natural abundance of 24.23%24.23\%. Calculate the relative atomic mass of chlorine.
  1. Write down the formula for relative atomic mass using percentage abundance.

    Relative Atomic Mass=(mass of isotope 1×%abundance 1)+(mass of isotope 2×%abundance 2)100\text{Relative Atomic Mass} = \frac{(\text{mass of isotope 1} \times \% \text{abundance 1}) + (\text{mass of isotope 2} \times \% \text{abundance 2})}{100}
  2. Substitute the given values into the formula.

    Relative Atomic Mass=(34.9689×75.77)+(36.9659×24.23)100\text{Relative Atomic Mass} = \frac{(34.9689 \times 75.77) + (36.9659 \times 24.23)}{100}
  3. Perform the multiplications.

    Relative Atomic Mass=(2649.600693)+(895.608997)100\text{Relative Atomic Mass} = \frac{(2649.600693) + (895.608997)}{100}
  4. Add the products and divide by 100.

    Relative Atomic Mass=3545.20969100\text{Relative Atomic Mass} = \frac{3545.20969}{100} Relative Atomic Mass=35.4520969\text{Relative Atomic Mass} = 35.4520969
  5. Round to an appropriate number of significant figures (usually two decimal places for RAM).

    Relative Atomic Mass≈35.45\text{Relative Atomic Mass} \approx 35.45

    The relative atomic mass of chlorine is 35.45.

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