Find the second derivative of y=x³−x²+2x+5

We substitute each $x$ value into the function to find the corresponding $y$ value.

For $x=14$:

$$y = 2(14) + 5 = 28 + 5 = 33$$

For $x=7$:

$$y = 2(7) + 5 = 14 + 5 = 19$$

For $x=3$:

$$y = 2(3) + 5 = 6 + 5 = 11$$

For $x=1$:

$$y = 2(1) + 5 = 2 + 5 = 7$$

For $x=2$:

$$y = 2(2) + 5 = 4 + 5 = 9$$

For $x=4$:

$$y = 2(4) + 5 = 8 + 5 = 13$$

The completed table is:

X	Y
14	33
7	19
3	11
1	7
2	9
4	13

For $x=3$:

$$y = 2(3) + 5$$ $$y = 6 + 5$$ $$y = \boxed{\textbf{11}}$$

For $x=7$:

$$y = 2(7) + 5$$ $$y = 14 + 5$$ $$y = \boxed{\textbf{19}}$$

For $x=1$:

$$y = 2(1) + 5$$ $$y = 2 + 5$$ $$y = \boxed{\textbf{7}}$$

For $x=4$:

$$y = 2(4) + 5$$ $$y = 8 + 5$$ $$y = \boxed{\textbf{13}}$$

For $x=0$:

$$y = 2(0) + 5$$ $$y = 0 + 5$$ $$y = \boxed{\textbf{5}}$$

For $x=2$:

$$y = 2(2) + 5$$ $$y = 4 + 5$$ $$y = \boxed{\textbf{9}}$$