Find the second derivative of the function y = (2x3+4) / (5x-6)2 using the quotient rule twice.

To find the second derivative $\frac{d^2y}{dx^2}$ of the function $y = \frac{2x^3+4}{(5x-6)^2}$, we will use the quotient rule twice. The quotient rule states that if $y = \frac{u}{v}$, then $\frac{dy}{dx} = \frac{u'v - uv'}{v^2}$.

Step 1: Find the first derivative, $\frac{dy}{dx}$.
Let $u = 2x^3+4$ and $v = (5x-6)^2$.
First, find the derivatives of $u$ and $v$:
$u' = \frac{d}{dx}(2x^3+4) =