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Define database and list three business applications and five advantages over paper systems.

Computer Science

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Question 17

a) i) Define Database (2mks)
A database is an organized collection of structured information, or data, typically stored electronically in a computer system. It is designed for efficient storage, retrieval, and management of data.

a) ii) Give three areas where databases may be used in business (3mks)

  • Customer Relationship Management (CRM): Storing customer details, purchase history, and interactions.
  • Inventory Management: Tracking stock levels, product information, and supplier details.
  • Financial Accounting: Managing transactions, ledgers, and financial records.
  • Human Resources: Storing employee information, payroll, and performance data.

b) i) State five advantages that modern database systems have over paper-based systems (5mks)

  • Reduced Data Redundancy: Data is stored once, minimizing duplication.
  • Improved Data Consistency: Ensures that data is uniform and accurate across the system.
  • Enhanced Data Security: Provides mechanisms for access control and data protection.
  • Easier Data Sharing: Multiple users can access and share data concurrently.
  • Faster Data Retrieval and Updates: Allows quick searching, sorting, and modification of data.
  • Better Data Integrity: Enforces rules to maintain the quality and reliability of data.
  • Reduced Storage Space: Digital storage is more compact than physical paper records.
  • Data Backup and Recovery: Facilitates easy backup and restoration of data in case of loss.

b) ii) STATE five major functions of DBMS in computerized information processing (5 mks)

  • Data Definition: Allows users to define the structure of the database, including data types, relationships, and constraints.
  • Data Manipulation: Provides tools for adding, deleting, modifying, and retrieving data from the database.
  • Data Security and Integrity: Manages user access, permissions, and ensures data accuracy and consistency through validation rules.
  • Data Storage Management: Handles the physical storage of data on disk and manages access to it.
  • Data Backup and Recovery: Provides utilities to create backups of the database and restore it in case of system failure or data loss.
  • Concurrency Control: Manages simultaneous access to the database by multiple users, preventing conflicts and ensuring data consistency.

Question 18

a) Describe the octal number system (2mks)
The octal number system is a base-8 number system, meaning it uses eight distinct digits (0, 1, 2, 3, 4, 5, 6, 7) to represent numbers. Each position in an octal number represents a power of 8.

b) Convert each of the following to the number system indicated:

i) 111.1012111.101_2 to decimal (2 marks)
To convert a binary number to decimal, multiply each digit by its corresponding power of 2.

111.1012=(1×22)+(1×21)+(1×20)+(1×2−1)+(0×2−2)+(1×2−3)111.101_2 = (1 \times 2^2) + (1 \times 2^1) + (1 \times 2^0) + (1 \times 2^{-1}) + (0 \times 2^{-2}) + (1 \times 2^{-3}) =(1×4)+(1×2)+(1×1)+(1×0.5)+(0×0.25)+(1×0.125)= (1 \times 4) + (1 \times 2) + (1 \times 1) + (1 \times 0.5) + (0 \times 0.25) + (1 \times 0.125) =4+2+1+0.5+0+0.125= 4 + 2 + 1 + 0.5 + 0 + 0.125 =7+0.625= 7 + 0.625 =7.62510= \boxed{\text{}7.625_{10}\text{}}

ii) 14.68751014.6875_{10} to binary (2 marks)
To convert a decimal number to binary, convert the integer and fractional parts separately.

  • Integer part (14): Divide by 2 and collect remainders. 14÷2=714 \div 2 = 7 R 0 7÷2=37 \div 2 = 3 R 1 3÷2=13 \div 2 = 1 R 1 1÷2=01 \div 2 = 0 R 1 Reading remainders from bottom up: 111021110_2

  • Fractional part (0.6875): Multiply by 2 and collect integer parts. 0.6875×2=1.375→10.6875 \times 2 = 1.375 \rightarrow 1 0.375×2=0.75→00.375 \times 2 = 0.75 \rightarrow 0 0.75×2=1.5→10.75 \times 2 = 1.5 \rightarrow 1 0.5×2=1.0→10.5 \times 2 = 1.0 \rightarrow 1 Reading integer parts from top down: 0.101120.1011_2

Combining the integer and fractional parts:

14.687510=1110.1011214.6875_{10} = \boxed{\text{}1110.1011_2\text{}}

c) Convert the number −1710-17_{10} into 8-bit i) Signed magnitude representation (2 marks)

  1. Convert the absolute value to binary

    171017_{10} to binary:
    17÷2=817 \div 2 = 8 R 1
    8÷2=48 \div 2 = 4 R 0
    4÷2=24 \div 2 = 2 R 0
    2÷2=12 \div 2 = 1 R 0
    1÷2=01 \div 2 = 0 R 1
    So, 1710=10001217_{10} = 10001_2.

  2. Represent in 8-bit signed magnitude

    In 8-bit signed magnitude, the leftmost bit (Most Significant Bit, MSB) is the sign bit (0 for positive, 1 for negative), and the remaining 7 bits represent the magnitude.
    The magnitude 10001210001_2 needs 5 bits. Padded to 7 bits, it becomes 001000120010001_2.
    Since the number is −1710-17_{10}, the sign bit is 1.

    Therefore, the 8-bit signed magnitude representation of −1710-17_{10} is:

    Sign bitMagnitude (7 bits)\text{Sign bit} \quad \text{Magnitude (7 bits)} 100100011 \quad 0010001 =100100012= \boxed{\text{}10010001_2\text{}}
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