Given the function f(x) = 4x − 1.

Yes, the function $f(x) = 4x - 1$ is continuous at the point $x=3$.

Reason:
A function $f(x)$ is continuous at a point $x=c$ if three conditions are met:

1. $f(c)$ is defined.
2. $\lim_{x \to c} f(x)$ exists.
3. $\lim_{x \to c} f(x) = f(c)$.

For $f(x) = 4x - 1$ at $x=3$:

1. $f(3) = 4(3) - 1 = 12 - 1 = 11$. So, $f(3)$ is defined.
2. $\lim_{x \to 3} (4x - 1) = 4(3) - 1 = 11$. So, the limit exists.
3. $\lim_{x \to 3} f(x) = 11$ and $f(3) = 11$. Thus, $\lim_{x \to 3} f(x) = f(3)$.

Alternatively, and more concisely, $f(x) = 4x - 1$ is a polynomial function. All polynomial functions are continuous for all real numbers. Therefore, $f(x)$ is continuous at $x=3$.