How do I find the Boolean equation from a K-map with one '1' and the rest 'don't cares'?

You're on a roll — Here's how to find the Boolean equation from the K-map: Step 1: Identify the values in the K-map. The K-map shows three variables: Q_A, Q_B, and Q_C. The columns represent Q_A (1 and 0). The rows represent Q_B Q_C (00, 01, 11, 10). The cell at Q_A=1, Q_B Q_C=00 contains a '1'. All other cells contain 'X', which typically denotes a 'don't care' condition in K-maps. We can use 'don't cares' to form larger groups and simplify the expression. Step 2: Group the '1's and 'don't cares' (X's) to form the largest possible groups of powers of 2. The '1' at (Q_A=1, Q_B=0, Q_C=0) must be covered. We can form a group of 4 cells by including this '1' and the three 'X's in the same column where Q_A=1. The cells in this group are: • Q_A=1, Q_B=0, Q_C=0 (value 1) • Q_A=1, Q_B=0, Q_C=1 (value X) • Q_A=1, Q_B=1, Q_C=1 (value X) • Q_A=1, Q_B=1, Q_C=0 (value X) Step 3: Write the Boolean expression for the formed group. For this group of 4 cells: • Q_A is constant at 1. • Q_B changes from 0 to 1 within the group, so it is eliminated. • Q_C changes from 0 to 1 within the group, so it is eliminated. Therefore, the simplified term for this group is Q_A. Step 4: Combine the terms. Since this single group covers the only '1' in the K-map, the simplified Boolean equation is just this term. The equation is: F = Q_A What's next?