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Solve the Boolean algebraic expression above, showing all the steps and laws used, in English

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Answer

See truth table above\text{See truth table above}

Step-by-step solution

4 steps

To obtain the truth table for the function F=ABˉ+BˉC+AˉCˉF = A\bar{B} + \bar{B}C + \bar{A}\bar{C}, we need to evaluate the function for all possible combinations of the input variables A, B, and C. Since there are three variables, there will be 23=82^3 = 8 rows in the truth table.

  1. List all possible combinations for A, B, and C.

  2. Calculate the inversions Aˉ\bar{A}, Bˉ\bar{B}, and Cˉ\bar{C}.

  3. Calculate each product term

    ABˉA\bar{B}, BˉC\bar{B}C, and AˉCˉ\bar{A}\bar{C}.

  4. Calculate the final function F by performing the OR operation on the three product terms

    F=ABˉ+BˉC+AˉCˉF = A\bar{B} + \bar{B}C + \bar{A}\bar{C}.

    Here is the truth table:

    ABCAˉBˉCˉABˉBˉCAˉCˉF00011100110011100101010101001101110000001000111001101010110111000100001110000000\begin{array}{|c|c|c|c|c|c|c|c|c|c|} \hline \textbf{A} & \textbf{B} & \textbf{C} & \mathbf{\bar{A}} & \mathbf{\bar{B}} & \mathbf{\bar{C}} & \mathbf{A\bar{B}} & \mathbf{\bar{B}C} & \mathbf{\bar{A}\bar{C}} & \textbf{F} \\ \hline 0 & 0 & 0 & 1 & 1 & 1 & 0 & 0 & 1 & 1 \\ 0 & 0 & 1 & 1 & 1 & 0 & 0 & 1 & 0 & 1 \\ 0 & 1 & 0 & 1 & 0 & 1 & 0 & 0 & 1 & 1 \\ 0 & 1 & 1 & 1 & 0 & 0 & 0 & 0 & 0 & 0 \\ 1 & 0 & 0 & 0 & 1 & 1 & 1 & 0 & 0 & 1 \\ 1 & 0 & 1 & 0 & 1 & 0 & 1 & 1 & 0 & 1 \\ 1 & 1 & 0 & 0 & 0 & 1 & 0 & 0 & 0 & 0 \\ 1 & 1 & 1 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \\ \hline \end{array}

    The final truth table for the function F=ABˉ+BˉC+AˉCˉF = A\bar{B} + \bar{B}C + \bar{A}\bar{C} is shown above.

    See truth table above\text{See truth table above}
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