Let the function have domain (-2, -1, 0, 1, 2, 3) and be defined by f(x) = x?

The domain of the function is given as $D = \{-2, -1, 0, 1, 2, 3\}$.
The function is defined by $f(x) = x$.

To find the range, we substitute each value from the domain into the function $f(x) = x$.
For $x = -2$, $f(-2) = -2$
For $x = -1$, $f(-1) = -1$
For $x = 0$, $f(0) = 0$
For $x = 1$, $f(1) = 1$
For $x = 2$, $f(2) = 2$
For $x = 3$, $f(3) = 3$

The range is the set of all output values.
Range $= \{-2, -1, 0, 1, 2, 3\}$

The range of the function is $\boxed{\{-2, -1, 0, 1, 2, 3\}}$.