Let the function have domain \-2,-1,0,1,2\ and be defined by f(x)=x2. (a) Show the table of the function and (b) What is the range of the function?

Here is the solution to the problem.

a) Show the table of the function

Step 1: Identify the domain and the function definition. The domain is $D = \{-2, -1, 0, 1, 2, 3\}$. The function is defined by $f(x) = x^2$.

Step 2: Calculate $f(x)$ for each value in the domain. For $x = -2$, $f(-2) = (-2)^2 = 4$ For $x = -1$, $f(-1) = (-1)^2 = 1$ For $x = 0$, $f(0) = (0)^2 = 0$ For $x = 1$, $f(1) = (1)^2 = 1$ For $x = 2$, $f(2) = (2)^2 = 4$ For $x = 3$, $f(3) = (3)^2 = 9$

Step 3: Create the table.

b) What is the range of the function

Step 1: List all the output values from the table in part (a). The output values are $\{4, 1, 0, 1, 4, 9\}$.

Step 2: Identify the unique values and list them in ascending order. The unique values are $0, 1, 4, 9$.

The range of the function is $\boxed{\{0, 1, 4, 9\}}$.