I can't understand the language your using please change those responses int English

English

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Answer

b

The device is efficient\text{The device is efficient}

Step-by-step solution

5 steps

Okay, my apologies! I will switch to English for you. Here is the solution to your question in English:

Part a· 2 steps

The device needed to rectify the voltage issue is a *step-up transformer

  1. Explain the structure of a transformer.

    A transformer consists of two coils of wire, a primary coil and a secondary coil, wound around a soft iron core. For a step-up transformer, the secondary coil has a greater number of turns than the primary coil.

  2. Explain how the transformer works.

    When an alternating current (AC) passes through the primary coil, it creates a changing magnetic field in the iron core. This changing magnetic field links with the secondary coil, inducing a voltage (EMF) in the secondary coil according to Faraday's Law of Induction. Since the secondary coil has more turns, the voltage is increased from 415 V to 2,000 V.

Part b

The device is efficient\text{The device is efficient}

To determine if the device is efficient, we need to calculate the power loss and compare it to the 5 W limit.

  1. Calculate the current flowing through the wires.

    We use the power formula P=VIP = VI.

    I=PVI = \frac{P}{V}

    Where P=2 kW=2000 WP = 2 \, \text{kW} = 2000 \, \text{W} and V=2000 VV = 2000 \, \text{V}.

    I=2000 W2000 V=1 AI = \frac{2000 \, \text{W}}{2000 \, \text{V}} = 1 \, \text{A}
  2. Calculate the power loss in the wires.

    The power loss (PlossP_{\text{loss}}) in the wires is given by the formula Ploss=I2RP_{\text{loss}} = I^2 R.
    Where I=1 AI = 1 \, \text{A} and R=2 ΩR = 2 \, \Omega.

    Ploss=(1 A)2×2 Ω=1 WP_{\text{loss}} = (1 \, \text{A})^2 \times 2 \, \Omega = 1 \, \text{W}
  3. Compare the power loss with the allowed limit.

    The calculated power loss is 1 W1 \, \text{W}.
    The allowed power loss limit is 5 W5 \, \text{W}.
    Since 1 W<5 W1 \, \text{W} < 5 \, \text{W}, the power loss is within the acceptable limit.

    Conclusion:
    The device is efficient.

    The device is efficient\boxed{\text{The device is efficient}}
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