Send detailed answers in English plz

Let $t$ be the number of hours past 7:00 AM.

• At 7:00 AM ($t=0$): 0 members
• At 8:00 AM ($t=1$): 1 member ($1^2$)
• At 9:00 AM ($t=2$): 4 members ($2^2$)
• At 10:00 AM ($t=3$): 9 members ($3^2$)
• At 11:00 AM ($t=4$): 16 members ($4^2$) The pattern for the number of members arrived is $t^2$.

2:00 PM is 7 hours after 7:00 AM ($14:00 - 7:00 = 7$ hours). So, $t=7$.
Number of members = $7^2 = 49$.

The meeting will start if at least 45 members have arrived.
Since 49 members have arrived, and $49 \ge 45$, the meeting will start.

The meeting will start by 2:00 PM.

Let $P$ be the unit price of one phone and $T$ be the constant transport cost.
For 5 phones:

For 8 phones:

Subtract equation (1) from equation (2):

Substitute the value of $P$ into equation (1):

The constant transport costs are Shs. 18,000.

Unit price $P = \text{Shs. } 120,000$.
Transport cost $T = \text{Shs. } 18,000$.

Total cost = (Number of phones $\times$ Unit price) + Transport cost
Total cost = $12P + T$
Total cost = $12(120,000) + 18,000$
Total cost = $1,440,000 + 18,000$
Total cost = 1,458,000

The amount to be charged for 12 phones is Shs. 1,458,000.

• Monday ($x=1$):

• Tuesday ($x=2$):

• Wednesday ($x=3$):

• Thursday ($x=4$):

• Friday ($x=5$):

• Saturday ($x=6$):

The points to plot are:

• (Monday, 10)
• (Tuesday, 12)
• (Wednesday, 12)
• (Thursday, 10)
• (Friday, 6)
• (Saturday, 0) The graph would be a downward-opening parabola passing through these points.

The function $f(x) = -x^2 + 5x + 6$ is a downward-opening parabola, so its maximum value occurs at its vertex.
The x-coordinate of the vertex for a quadratic function $ax^2 + bx + c$ is given by $x = -\frac{b}{2a}$.
Here, $a=-1$ and $b=5$.

This means the maximum value occurs between day 2 (Tuesday) and day 3 (Wednesday).

From the calculations above:

• Tuesday ($x=2$): 12 trees were cut.
• Wednesday ($x=3$): 12 trees were cut.

The maximum number of trees were cut on Tuesday and Wednesday.