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A satellite is at position P (52°S, 114°E) and another is at Q (52°S, 66°W). The radius of the Earth is 6370 km. Calculate (a) the difference in longitude between P and Q, and (b) the shortest distanc

Geography

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Answer

a

180∘180^\circ

Step-by-step solution

3 steps

Here's the solution to the problem:

Given:
Earth's radius R=6370 kmR = 6370 \text{ km}
Position of P: (52∘S,114∘E)(52^\circ \text{S}, 114^\circ \text{E})
Position of Q: (52∘S,66∘W)(52^\circ \text{S}, 66^\circ \text{W})

Part a· 2 steps

Find the difference in longitude between two points P and Q.

  1. Identify the longitudes of P and Q.

    Longitude of P = 114∘E114^\circ \text{E}
    Longitude of Q = 66∘W66^\circ \text{W}

  2. Calculate the difference in longitude.

    Since one point is East and the other is West, the difference is the sum of their absolute longitudes.

    Difference in longitude=114∘+66∘=180∘\text{Difference in longitude} = 114^\circ + 66^\circ = 180^\circ

    The difference in longitude is 180∘\boxed{180^\circ}.

Part b(i)· 1 step

The Latitude in km (to 1 whole number).

Calculate the shortest distance between points P and Q along-

  1. Identify the common latitude and the difference in longitude.

    Both P and Q are on latitude 52∘S52^\circ \text{S}.
    Difference in longitude θ=180∘\theta = 180^\circ (from

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