A three-phase 132 kV, 50 Hz transmission line 180 km long consists of three conductors each of diameter 1.2 cm and spaced 2.7 m apart in an equilateral triangle formation. The temperature and atmospheric pressure are 30°C and 750 mm of mercury respectively. If the breakdown strength of air is 30 kV/cm (peak) and the irregularity factor is 0.84. Determine the critical disruptive voltage and total corona power loss.

Question

Asked on March 26, 2026Physics

This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.

Accepted Answer · 2026-03-26T05:38:23.312Z

Here are the solutions to the problems: Problem 1: Corona Discharge Calculation a) (i) Critical disruptive voltage: Step 1: Calculate the air density correction factor (). Given temperature T = 30 \, ^ and pressure P = 750 \, mm of Hg. We use 25 \, ^ and 760 \, mm of Hg as standard conditions for g_0. = (P)/(760) × (273 + 25)/(273 + T) = 7507

Accepted Answer · 2026-03-26T05:38:23.312Z

Here are the solutions to the problems: Problem 1: Corona Discharge Calculation a) (i) Critical disruptive voltage: Step 1: Calculate the air density correction factor (). Given temperature T = 30 \, ^ and pressure P = 750 \, mm of Hg. We use 25 \, ^ and 760 \, mm of Hg as standard conditions for g_0. = (P)/(760) × (273 + 25)/(273 + T) = 7507

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