This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
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Item 3: a) Graphically understand the motion of the bus up to the point when it was brought to rest. Step 1: Identify the phases of motion and their corresponding velocities and times. • Phase 1 (Constant velocity): The bus moves at 15 ms^-1 for 1 minute (60 s). • Phase 2 (Acceleration): The bus accelerates from 15 ms^-1 to 25 ms^-1 in 30 s. This occurs from t=60 s to t=90 s. • Phase 3 (Constant velocity): The bus maintains a speed of 25 ms^-1 for 3 minutes (180 s). This occurs from t=90 s to t=270 s. • Phase 4 (Deceleration): The bus applies brakes and comes to rest (0 ms^-1) in 30 s. This occurs from t=270 s to t=300 s. Step 2: Describe the velocity-time graph. The velocity-time graph would show: • A horizontal line at v = 15 ms^-1 from t=0 s to t=60 s. • A straight line sloping upwards from (60 s, 15 ms^-1) to (90 s, 25 ms^-1). • A horizontal line at v = 25 ms^-1 from t=90 s to t=270 s. • A straight line sloping downwards from (270 s, 25 ms^-1) to (300 s, 0 ms^-1). b) Estimate the average speed of the bus for the motion. Step 1: Calculate the distance covered in each phase. • Phase 1: d_1 = 15 ms^-1 × 60 s = 900 m • Phase 2: d_2 = 15 ms^-1 + 25 ms^-12 × 30 s = 20 ms^-1 × 30 s = 600 m • Phase 3: d_3 = 25 ms^-1 × 180 s = 4500 m • Phase 4: d_4 = 25 ms^-1 + 0 ms^-12 × 30 s = 12.5 ms^-1 × 30 s = 375 m Step 2: Calculate the total distance and total time. Total distance D = 900 m + 600 m + 4500 m + 375 m = 6375 m Total time T = 60 s + 30 s + 180 s + 30 s = 300 s Step 3: Calculate the average speed. Average speed = Total distanceTotal time Average speed = 6375 m300 s = ✂️ _That answer was long and got cut off. Reply continue and I'll finish it._