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To find the distance between two points on the same parallel of latitude, we use the formula:

Geography

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Answer

9053.30 km\text{9053.30 km}

Step-by-step solution

4 steps

To find the distance between two points on the same parallel of latitude, we use the formula:

D=θ360∘×2πRcos⁡(ϕ)D = \frac{\theta}{360^\circ} \times 2\pi R \cos(\phi)

where:

  • θ\theta is the difference in longitudes.
  • RR is the radius of the Earth.
  • ϕ\phi is the common latitude.
  • π\pi is approximately 3.14.

From the problem statement, we are given:
Point P: (27∘N,6∘W)(27^\circ \text{N}, 6^\circ \text{W})
Point Q: (27∘N,97∘W)(27^\circ \text{N}, 97^\circ \text{W})
Radius of Earth R=6400 kmR = 6400 \text{ km} (from z=6400z=6400)
π=3.14\pi = 3.14 (from x=3.14x=3.14)

  1. Identify the common latitude and calculate the difference in longitudes.

    The common latitude is ϕ=27∘N\phi = 27^\circ \text{N}.
    The longitudes are 6∘W6^\circ \text{W} and 97∘W97^\circ \text{W}. Since both are in the West, the difference in longitude (θ\theta) is:

    θ=∣97∘−6∘∣=91∘\theta = |97^\circ - 6^\circ| = 91^\circ
  2. Substitute the values into the distance formula.

    D=91∘360∘×2×3.14×6400 km×cos⁡(27∘)D = \frac{91^\circ}{360^\circ} \times 2 \times 3.14 \times 6400 \text{ km} \times \cos(27^\circ)
  3. Calculate the value of cos⁡(27∘)\cos(27^\circ).

    cos⁡(27∘)≈0.8910\cos(27^\circ) \approx 0.8910
  4. Perform the calculation.

    D=91360×2×3.14×6400×0.8910D = \frac{91}{360} \times 2 \times 3.14 \times 6400 \times 0.8910 D=0.25277...×40192×0.8910D = 0.25277... \times 40192 \times 0.8910 D=10160.88...×0.8910D = 10160.88... \times 0.8910 D≈9053.30 kmD \approx 9053.30 \text{ km}

    The distance between points P and Q is approximately 9053.30 km\text{9053.30 km}.

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