Work this one out. How to write a field report. -river discharge calculate 158 width, 9ft depth, and velocity 0.02 m/s. -water volume 22mm and infiltration rate 1 minute 16 Seconds.

Geography

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Answer

2.6 m3/s\text{2.6 m}^3\text{/s}

0.29 mm/s\text{0.29 mm/s}

Step-by-step solution

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Let's break this down.

1. How to write a field report
A field report is a document that records observations and analysis from a specific site or event. It typically includes an introduction (stating the purpose, location, and date), methodology (describing data collection methods), observations/results (presenting detailed findings), a discussion (interpreting the data and noting limitations), and a conclusion (summarizing key insights).

2. Calculate river discharge
To calculate river discharge, we need the cross-sectional area and the velocity.

  1. Convert width and depth from feet to meters.

    Given:
    Width = 158 ft
    Depth = 9 ft
    Velocity = 0.02 m/s
    Conversion factor: 1 ft=0.3048 m1 \text{ ft} = 0.3048 \text{ m}

    Width in meters=158 ft×0.3048 m/ft=48.1584 m\text{Width in meters} = 158 \text{ ft} \times 0.3048 \text{ m/ft} = 48.1584 \text{ m} Depth in meters=9 ft×0.3048 m/ft=2.7432 m\text{Depth in meters} = 9 \text{ ft} \times 0.3048 \text{ m/ft} = 2.7432 \text{ m}

  2. Calculate the cross-sectional area (AA).

    A=width×depthA = \text{width} \times \text{depth} A=48.1584 m×2.7432 m=132.1209 m2A = 48.1584 \text{ m} \times 2.7432 \text{ m} = 132.1209 \text{ m}^2

  3. Calculate the river discharge (QQ).

    The formula for discharge is Q=A×VQ = A \times V.

    Q=132.1209 m2×0.02 m/s=2.642418 m3/sQ = 132.1209 \text{ m}^2 \times 0.02 \text{ m/s} = 2.642418 \text{ m}^3\text{/s}

    Rounding to two significant figures based on the velocity (0.02 m/s):

    Q≈2.6 m3/sQ \approx \boxed{\text{2.6 m}^3\text{/s}}

    3. Calculate infiltration rate
    Assuming "water volume 22mm" is the depth of water that infiltrated and "1 minute 16 seconds" is the time taken.

  4. Convert the time to seconds.

    1 minute 16 seconds=(1×60 s)+16 s=60 s+16 s=76 s1 \text{ minute } 16 \text{ seconds} = (1 \times 60 \text{ s}) + 16 \text{ s} = 60 \text{ s} + 16 \text{ s} = 76 \text{ s}

  5. Calculate the infiltration rate (IRI_R).

    IR=Infiltrated depthTimeI_R = \frac{\text{Infiltrated depth}}{\text{Time}} IR=22 mm76 s≈0.28947 mm/sI_R = \frac{22 \text{ mm}}{76 \text{ s}} \approx 0.28947 \text{ mm/s}

    Rounding to two significant figures:

    IR≈0.29 mm/sI_R \approx \boxed{\text{0.29 mm/s}}
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