Calculate the volume flux of water given the piston's cross-sectional area, movement distance, and time.

Question

ScanSolve AI Tutor · Accepted Answer

Here's how to calculate the volume flux of water:

Identify the given values for the movement of the piston in section A-B.
The cross-sectional area of the piston is $A = 1.5 \, \text{cm}^2$ .
The distance the piston moves is $d = 12 \, \text{cm}$ .
The time taken for this movement is $t = 3 \, \text{s}$ .
Calculate the volume of water displaced by the piston.
The volume displaced is given by the product of the cross-sectional area and the distance moved.
$V = A \times d$ $V = 1.5 \, \text{cm}^2 \times 12 \, \text{cm}$ $V = 18 \, \text{cm}^3$
Calculate the volume flux (volume flow rate).
The volume flux ( $Q$ ) is the volume of water displaced per unit time.
$Q = \frac{V}{t}$ $Q = \frac{18 \, \text{cm}^3}{3 \, \text{s}}$ $Q = 6 \, \text{cm}^3/\text{s}$
The volume flux of water is $\text{6 cm}^3/\text{s}$ .

Answer