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Given that the roots of the equation 3x² − 4x + 2 = 0 are alpha and beta.

Mathematics

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1. (i) Given that the roots of the equation 3x2−4x+2=03x^2 - 4x + 2 = 0 are α\alpha and β\beta.

a) Show that α3+β3=−827\alpha^3 + \beta^3 = -\frac{8}{27}.

Step 1: Identify the sum and product of roots from the given quadratic equation 3x2−4x+2=03x^2 - 4x + 2 = 0.
For ax2+bx+c=0ax^2 + bx + c = 0, the sum of roots is α+β=−ba\alpha + \beta = -\frac{b}{a} and the product of roots is αβ=ca\alpha\beta = \frac{c}{a}.
Here, a=3a=3, $

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