This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
ScanSolve AI Answer
Here are the solutions to your questions: 1.2) Step 1: Determine the number of 5m rolls needed for 2019 m of fencing. Number of rolls = Total lengthLength per roll = 2019 m5 m/roll = 403.8 rolls Since you cannot buy a fraction of a roll, you must purchase 404 rolls to cover the entire length. Step 2: Calculate the total cost. Total cost = Number of rolls × Cost per roll Total cost = 404 × R162.50 = R65650.00 The final answer is R65650.00. 1.3) Assumption: The "Maximum space of 4.8cm" is a typo and should be 4.8 m, as 4.8 cm is impractical for fence pole spacing. We will use 4.8 m spacing. Step 1: Calculate the number of intervals for the 2019 m fence with 4.8 m spacing. Number of intervals = Total lengthSpacing = 2019 m4.8 m/interval = 420.625 Step 2: Determine the number of poles. For a linear fence, the number of poles is the number of intervals rounded up, plus one for the starting pole. Number of poles = 420.625 + 1 = 421 + 1 = 422 poles The final answer is 422 poles. 1.4) Step 1: Calculate the cost if poles are bought in groups of 6 and individually for the remainder. Total poles needed: 422. Number of groups of 6: Number of groups = (422)/(6) = 70 with a remainder of 2 So, 70 groups of 6 poles will be bought, and 2 poles will be bought individually. Cost for groups: 70 × R500 = R35000. Cost for individual poles: 2 × R98.00 = R196.00. Total cost (groups + singles): R35000 + R196.00 = R35196.00. Step 2: Calculate the cost if all poles are bought individually. Total cost (individually) = 422 × R98.00 = R41356.00 Step 3: Compare the costs. The cost of buying in groups and remaining singles (R35196.00) is less than buying all individually (R41356.00). The final answer is R35196.00. That's 2 down. 3 left today — send the next one.